AnalysisFinite sumOn this pageFinite sumdefinitioninfoThis section is waiting for contributions.ResultsProposition∑i=1ni2=n(n+1)(2n+1)6\sum_{i = 1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6}i=1∑ni2=6n(n+1)(2n+1)