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Modulus

Let zCz \in \mathbb C. We note (z)\Re(z) the real part of zz and (z)\Im(z) the imaginary part of zz.

Definition

Definition

for all zCz \in \mathbb C, the modulus of zz is the positive real number denoted z|z| defined by

z=zz=(z)2+(z)2.|z| = \sqrt{z\overline z} = \sqrt{\Re(z)^2 + \Im(z)^2}.

Results

Proposition

For all complex number zz, we have:

  • z=zˉ|z| = |\bar z|,
  • z=0 if, and only if, z=0z = 0 \text{ if, and only if, } |z| = 0,
  • z\Re z \leqslant |\Re z| \leqslant |z| and zzz\Im z \leqslant |\Im z| \leqslant |z|.
Proof

Use the definition of modulus.

Proposition

For any nonzero complex number zz, we have 1z=zˉz2\frac{1}{z} = \frac{\bar z}{|z|^2}, and,

z=1 if, and only if ,1z=zˉ|z| = 1 \text{ if, and only if }, \frac{1}{z} = \bar z
Proposition

For any z1Cz_1 \in \mathbb C and any z2Cz_2 \in \mathbb C, we have

z1z2=z1z2 and, if z20,z1z2=z1z2.|z_1z_2| = |z_1||z_2| \quad \text{ and, if } z_2 \neq 0, \quad \left |\frac{z_1}{z_2}\right | = \frac{|z_1|}{|z_2|}.
Proposition : Triangle inequalities

For any z1Cz_1 \in \mathbb C and z2Cz_2 \in \mathbb C, we have

z1+z2z1+z2,|z_1 + z_2| \leqslant |z_1| + |z_2|,

and

z1z2z1z2,\left ||z_1| - |z_2| \right | \leqslant |z_1 - z_2|,

with equality if, and only if, kR+z2=kz1 or z1=kz2\exists k \in \mathbb R_+ \quad z_2 = kz_1 \text{ or } z_1 = kz_2.